Physics › Magnetic fields › Force on a moving charge
Force on a moving charge
Strip the wire away and the rule survives for a single flying charge: F = BQv, always at right angles to the motion. A force that can never do work can only steer, and steering at constant speed draws circles, and the cyclotron is built on precisely that.
Builds on Magnetic flux density and the force on a wire and Circular motion.
IN THIS TOPIC
- Use F = BQv for a charge moving perpendicular to the field, with the correct direction for either sign.
- Explain why the path is a circle and derive r = mv/BQ.
- Describe the cyclotron: magnetic steering, electric acceleration, a widening spiral.
WHAT YOU PROBABLY THINK
Magnetic fields can speed particles up.
One charge, same rule
A current is charge in motion, so the wire's force law has a single-particle version. A charge Q moving at speed v at right angles to a field of flux density B feels
with the direction from Fleming's left hand once more, remembering that the seCond finger follows conventional current: a negative charge moving right counts as conventional current moving left, so electrons deflect exactly opposite to protons in the same field. A stationary charge, with v = 0, feels nothing at all.
Circles, because no work is done
Because the force is always perpendicular to the velocity, it can never do work on the charge: the speed never changes, only the direction, which disposes of the opening misconception outright. A constant-magnitude force forever at right angles to the motion is precisely the condition for circular motion, with F = BQv in the centripetal seat. Setting the two faces equal, BQv = mv2/r, gives the radius:
so faster or heavier particles sweep wider circles, while stronger fields and bigger charges bend tighter. This one relation is how bubble-chamber photographs are read: the curvature of a track hands over the particle's momentum, and the direction of curl hands over its sign.
The cyclotron
The spec names the cyclotron as the application. Two hollow D-shaped electrodes sit in a uniform magnetic field, with an alternating pd across the gap between them. Inside each dee the magnetic field steers the particle round a half-circle; at each gap crossing the electric field does the accelerating, timed to push whichever way the particle is crossing. Every crossing raises v, and by r = mv/BQ every half-circle is wider than the last: the path is an outward spiral, and the particle exits at the rim with the energy of many small kicks. The design rests on that division of labour: magnetic fields steer for free, electric fields do the work.
THE EXAM BIT
- F = BQv needs the perpendicular condition stated, and gives zero for a charge moving along the field or standing still.
- Sign handling first: convert the particle's motion to conventional current before applying the left hand. Electrons curl opposite to protons.
- The no-work argument earns marks verbatim: the force is perpendicular to the velocity, so no work is done and the speed is constant; only the direction changes.
- Derive r = mv/BQ by equating BQv to mv2/r; the derivation is quick and frequently asked.
- For the cyclotron, split the jobs cleanly: the magnetic field provides the circular steering, the alternating electric field between the dees provides the energy. Mixing them up loses the explanation marks.
CHECK YOURSELF
An electron moves at 2.0 × 107 m s−1 at right angles to a field of 0.50 mT. Find the force on it and the radius of its circular path.
Show a hint
BQv for the force; then let it be the centripetal force.
Show the answer
F = BQv = 5.0 × 10−4 × 1.60 × 10−19 × 2.0 × 107 = 1.6 × 10−15 N.
r = mv/BQ = (9.11 × 10−31 × 2.0 × 107) / (5.0 × 10−4 × 1.60 × 10−19) = 0.23 m.
The speed stays 2.0 × 107 m s−1 the whole way round: the field steered the electron without giving it a single joule.
F = BQv steers and never works: circles at constant speed.
Radius mv/BQ: momentum written as curvature.
No animated video for this topic yet; these notes stand alone. InkPhysics on YouTube.